PhysicsMedium120×since 2002Q6740The electric field component of a monochromatic radiation is given by E→\overrightarrow EE = 2 E₀ i^\widehat ii cos kz cos ω\omegaωt Its magnetic field B→\overrightarrow BB is then given by :A2E0c{{2{E_0}} \over c}c2E0 j^\widehat jj sin kz cos ω\omegaωtB−-− 2E0c{{2{E_0}} \over c}c2E0 j^\widehat jj sin kz sin ω\omegaωtC2E0c{{2{E_0}} \over c}c2E0 j^\widehat jj sin kz sin ω\omegaωtD2E0c{{2{E_0}} \over c}c2E0 j^\widehat jj cos kz cos ω\omegaωtCheck answerSkip