The electric field between the two parallel plates of a capacitor of 1.5 μ F capacitance drops to one third of its initial value in 6.6 μ s when the plates are connected by a thin wire. The resistance of this wire is _ _ _ _ Ω. (Given, log 3=1.1)

Electrostatics: JEE Main 2024 Physics question

JEE Main 2024 · 5 Apr, Morning shift · Q58

JEE Main 20245 Apr, Morning shiftPhysicsMediumElectrostatics167× since 2002

The electric field between the two parallel plates of a capacitor of

1.5 \mu \mathrm{F}

capacitance drops to one third of its initial value in

6.6 \mu \mathrm{s}

when the plates are connected by a thin wire. The resistance of this wire is ________

\Omega

. (Given,

\log 3=1.1

)

Your answerType your answer. Integers and decimals are accepted.

JEE Main 2024 Electrostatics Question with Answer (5 Apr Morning shift, Q58) | JEE Arc