JEE Main 20244 Apr, Morning shiftChemistryMediumAtomic Structure113× since 2002The de-Broglie's wavelength of an electron in the 4th 4^{\text {th }}4th orbit is ________ πa0\pi \mathrm{a}_0πa0. (a0=\mathrm{a}_0=a0= Bohr's radius)Your answerType your answer. Integers and decimals are accepted.CheckSkip · show solution