JEE Main 20254 Apr, Evening shiftChemistryEasyCoordination Compounds198× since 2002The correct order of [FeF6]3−\mathrm{[FeF_6]^{3-}}[FeF6]3−, [CoF6]3−\mathrm{[CoF_6]^{3-}}[CoF6]3−, [Ni(CO)4]\mathrm{[Ni(CO)_4]}[Ni(CO)4] and [Ni(CN)4]2−\mathrm{[Ni(CN)_4]^{2-}}[Ni(CN)4]2− complex species based on the number of unpaired electrons present is :AOption A. [Ni(CN)4]2−>[FeF6]3−>[CoF6]3−>[Ni(CO)4]\mathrm{[Ni(CN)_4]^{2-} > [FeF_6]^{3-} > [CoF_6]^{3-} > [Ni(CO)_4]}[Ni(CN)4]2−>[FeF6]3−>[CoF6]3−>[Ni(CO)4]BOption B. [CoF6]3−>[FeF6]3−>[Ni(CO)4]>[Ni(CN)4]2−\mathrm{[CoF_6]^{3-} > [FeF_6]^{3-} > [Ni(CO)_4] > [Ni(CN)_4]^{2-}}[CoF6]3−>[FeF6]3−>[Ni(CO)4]>[Ni(CN)4]2−COption C. [FeF6]3−>[CoF6]3−>[Ni(CN)4]2−=[Ni(CO)4]\mathrm{[FeF_6]^{3-} > [CoF_6]^{3-} > [Ni(CN)_4]^{2-} = [Ni(CO)_4]}[FeF6]3−>[CoF6]3−>[Ni(CN)4]2−=[Ni(CO)4]DOption D. [FeF6]3−>[CoF6]3−>[Ni(CN)4]2−>[Ni(CO)4]\mathrm{[FeF_6]^{3-} > [CoF_6]^{3-} > [Ni(CN)_4]^{2-} > [Ni(CO)_4]}[FeF6]3−>[CoF6]3−>[Ni(CN)4]2−>[Ni(CO)4]CheckSkip · show solution
