The cell potential for Zn|Zn²⁺(aq)||Snˣ⁺| Sn is 0.801 ~V at 298 ~K. The reaction quotient for the above reaction is 10⁻². The number of electrons involved in the given electrochemical cell reaction is _ _ _ _ _ _. (. Given: E Zn²⁺ Zn ^(o)=-0.763 ~V, E Snˣ⁺ Sn ^(o)=+0.008 ~V and.(2.303 RT)/F=0.06 ~V)

Redox Reactions and Electrochemistry: JEE Main 2022 Chemistry question

JEE Main 2022 · 25 Jul, Morning shift · Q8

JEE Main 202225 Jul, Morning shiftChemistryHardRedox Reactions and Electrochemistry138× since 2002

The cell potential for

\mathrm{Zn}\left|\mathrm{Zn}^{2+}(\mathrm{aq})\right|\left|\mathrm{Sn}^{x+}\right| \mathrm{Sn}

0.801 \mathrm{~V}

298 \mathrm{~K}

. The reaction quotient for the above reaction is

10^{-2}

. The number of electrons involved in the given electrochemical cell reaction is ____________.

\left(\right.

Given

: \mathrm{E}_{\mathrm{Zn}^{2+} \mid \mathrm{Zn}}^{\mathrm{o}}=-0.763 \mathrm{~V}, \mathrm{E}_{\mathrm{Sn}^{x+} \mid \mathrm{Sn}}^{\mathrm{o}}=+0.008 \mathrm{~V}

and

\left.\frac{2.303 \mathrm{RT}}{\mathrm{F}}=0.06 \mathrm{~V}\right)

Your answerType your answer. Integers and decimals are accepted.

JEE Main 2022 Redox Reactions and Electrochemistry Question with Answer (25 Jul Morning shift, Q8) | JEE Arc