The Born-Haber cycle for KCl is evaluated with the following data: Δ f H^Θ for KCl = - 436.7 kJ mol⁻¹; Δ sub H^Θ for K = 89.2 kJ mol⁻¹; Δ ionization H^Θ for K = 419.0 kJ mol⁻¹; Δ electron gain H^Θ for Cl_(g) = - 348.6 kJ mol⁻¹; Δ bond H^Θ for Cl₂ = 243.0 kJ mol⁻¹ The magnitude of lattice enthalpy of KCl in kJ mol⁻¹ is _ _ _ _ _ _ _ (Nearest integer)

Chemical Thermodynamics: JEE Main 2021 Chemistry question

JEE Main 2021 · 26 Aug, Morning shift · Q20

JEE Main 202126 Aug, Morning shiftChemistryHardChemical Thermodynamics84× since 2002

The Born-Haber cycle for KCl is evaluated with the following data :

{\Delta _f}{H^\Theta }

for KCl =

-

436.7 kJ mol^

-

1 ;

{\Delta _{sub}}{H^\Theta }

for K = 89.2 kJ mol^

-

1 ;

{\Delta _{ionization}}{H^\Theta }

for K = 419.0 kJ mol^

-

1 ;

{\Delta _{electron\,gain}}{H^\Theta }

for Cl_(g) =

-

348.6 kJ mol^

-

1 ;

{\Delta _{bond}}{H^\Theta }

for Cl₂ = 243.0 kJ mol^

-

1 The magnitude of lattice enthalpy of KCl in kJ mol^

-

1 is _____________ (Nearest integer)

Your answerType your answer. Integers and decimals are accepted.

JEE Main 2021 Chemical Thermodynamics Question with Answer (26 Aug Morning shift, Q20) | JEE Arc