JEE Main 202131 Aug, Evening shiftMathematicsMediumThree Dimensional Geometry249× since 2002Suppose, the line x−2α=y−2−5=z+22{{x - 2} \over \alpha } = {{y - 2} \over { - 5}} = {{z + 2} \over 2}αx−2=−5y−2=2z+2 lies on the plane x+3y−2z+β=0x + 3y - 2z + \beta = 0x+3y−2z+β=0. Then (α+β)(\alpha + \beta )(α+β) is equal to _______.Your answerType your answer. Integers and decimals are accepted.CheckSkip · show solution
