Solid Lead nitrate is dissolved in 1 litre of water. The solution was found to boil at 100.15° C. When 0.2 mol of NaCl is added to the resulting solution, it was observed that the solution froze at -0.8° C. The solubility product of PbCl ₂ formed is _ _ _ _ _ × 10 ⁻⁶ at 298 K. (Nearest integer) Given: K b =0.5 K kg mol ⁻¹ and K f =1.8 K kg mol ⁻¹. Assume molality to the equal to molarity in all cases.

Solutions: JEE Main 2023 Chemistry question

JEE Main 2023 · 29 Jan, Morning shift · Q18

JEE Main 202329 Jan, Morning shiftChemistryHardSolutions71× since 2002

Solid Lead nitrate is dissolved in 1 litre of water. The solution was found to boil at 100.15

^\circ

C. When 0.2 mol of NaCl is added to the resulting solution, it was observed that the solution froze at

-0.8^\circ

C. The solubility product of PbCl

_2

formed is __________

\times

^{-6}

at 298 K. (Nearest integer) Given :

\mathrm{K_b=0.5}

K kg mol

^{-1}

and

\mathrm{K_f=1.8}

K kg mol

^{-1}

. Assume molality to the equal to molarity in all cases.

Your answerType your answer. Integers and decimals are accepted.

JEE Main 2023 · 29 Jan, Morning shift · Q18

JEE Main 202329 Jan, Morning shiftChemistryHardSolutions71× since 2002

Solid Lead nitrate is dissolved in 1 litre of water. The solution was found to boil at 100.15

^\circ

C. When 0.2 mol of NaCl is added to the resulting solution, it was observed that the solution froze at

-0.8^\circ

C. The solubility product of PbCl

_2

formed is __________

\times

^{-6}

at 298 K. (Nearest integer) Given :

\mathrm{K_b=0.5}

K kg mol

^{-1}

and

\mathrm{K_f=1.8}

K kg mol

^{-1}

. Assume molality to the equal to molarity in all cases.

Your answerType your answer. Integers and decimals are accepted.