Resonance in X₂Y can be represented as X = X = Y:X X - Y:. The enthalpy of formation of X₂Y (X X(g) + 1/2 Y = Y(g) → X₂Y(g)) is 80 kJ mol ⁻¹. The magnitude of resonance energy of X₂Y is _ _ _ kJ mol ⁻¹ (nearest integer value). Given: Bond energies of X X, X = X, Y = Y and X = Y are 940, 410, 500 and 602 kJ mol ⁻¹ respectively. valence X: 3, Y: 2

Chemical Thermodynamics: JEE Main 2025 Chemistry question

JEE Main 2025 · 8 Apr, Evening shift · Q74

JEE Main 20258 Apr, Evening shiftChemistryHardChemical Thermodynamics84× since 2002

Resonance in

\mathrm{X_2Y}

can be represented as

\overset{\ominus}{\ddot{X}}{=}\overset{\oplus}{X}{=}\ddot{Y} \leftrightarrow :X{\equiv}\overset{\oplus}{X}{-}\overset{\ominus}{\ddot{Y}}:

. The enthalpy of formation of

\mathrm{X_2Y}

\left(X{\equiv}X(g) + \frac12 Y{=}Y(g) \rightarrow X_2Y(g)\right)

is 80 kJ mol

^{-1}

. The magnitude of resonance energy of

\mathrm{X_2Y}

is ______ kJ mol

^{-1}

(nearest integer value). Given: Bond energies of

X{\equiv}X

X{=}X

Y{=}Y

and

X{=}Y

are 940, 410, 500 and 602 kJ mol

^{-1}

respectively. valence X: 3, Y: 2

Your answerType your answer. Integers and decimals are accepted.

JEE Main 2025 Chemical Thermodynamics Question with Solution (8 Apr Evening shift, Q74) | JEE Arc