Resistance of a conductivity cell (cell constant 129 ~m⁻¹) filled with 74.5 ppm solution of KCl is 100 Ω (labelled as solution 1). When the same cell is filled with KCl solution of 149 ppm, the resistance is 50 Ω (labelled as solution 2). The ratio of molar conductivity of solution 1 and solution 2 is i.e. (₁)/(₂)=x × 10⁻³. The value of x is _ _ _ _ _. (Nearest integer) Given, molar mass of KCl is 74.5 ~g ~mol⁻¹.

Redox Reactions and Electrochemistry: JEE Main 2022 Chemistry question

JEE Main 2022 · 29 Jul, Morning shift · Q9

JEE Main 202229 Jul, Morning shiftChemistryHardRedox Reactions and Electrochemistry138× since 2002

Resistance of a conductivity cell (cell constant

129 \mathrm{~m}^{-1}

) filled with

74.5 \,\mathrm{ppm}

solution of

\mathrm{KCl}

100 \,\Omega

(labelled as solution 1). When the same cell is filled with

\mathrm{KCl}

solution of

149 \,\mathrm{ppm}

, the resistance is

50 \,\Omega

(labelled as solution 2). The ratio of molar conductivity of solution 1 and solution 2 is i.e.

\frac{\wedge_{1}}{\wedge_{2}}=x \times 10^{-3}

. The value of

x

is __________. (Nearest integer) Given, molar mass of

\mathrm{KCl}

74.5 \mathrm{~g} \mathrm{~mol}^{-1}

Your answerType your answer. Integers and decimals are accepted.

JEE Main 2022 Redox Reactions and Electrochemistry Question with Answer (29 Jul Morning shift, Q9) | JEE Arc

JEE Main 2022 · 29 Jul, Morning shift · Q9

JEE Main 202229 Jul, Morning shiftChemistryHardRedox Reactions and Electrochemistry138× since 2002

Resistance of a conductivity cell (cell constant

129 \mathrm{~m}^{-1}

) filled with

74.5 \,\mathrm{ppm}

solution of

\mathrm{KCl}

100 \,\Omega

(labelled as solution 1). When the same cell is filled with

\mathrm{KCl}

solution of

149 \,\mathrm{ppm}

, the resistance is

50 \,\Omega

(labelled as solution 2). The ratio of molar conductivity of solution 1 and solution 2 is i.e.

\frac{\wedge_{1}}{\wedge_{2}}=x \times 10^{-3}

. The value of

x

is __________. (Nearest integer) Given, molar mass of

\mathrm{KCl}

74.5 \mathrm{~g} \mathrm{~mol}^{-1}

Your answerType your answer. Integers and decimals are accepted.