The length of the chord of the ellipse (x²)/4 + (y²)/2 = 1, whose mid-point is (1, 1/2), is:

Coordinate Geometry: JEE Main 2025 Mathematics question

JEE Main 2025 · January, Unspecified (session-level dataset) · Q234

JEE Main 2025January, Unspecified (session-level dataset)MathematicsMediumCoordinate Geometry478× since 2002

The length of the chord of the ellipse

\frac{x^2}{4} + \frac{y^2}{2} = 1

, whose mid-point is

\left(1, \frac{1}{2}\right)

, is:

JEE Main 2025 · January, Unspecified (session-level dataset) · Q234

JEE Main 2025January, Unspecified (session-level dataset)MathematicsMediumCoordinate Geometry478× since 2002

The length of the chord of the ellipse

\frac{x^2}{4} + \frac{y^2}{2} = 1

, whose mid-point is

\left(1, \frac{1}{2}\right)

, is: