Statistics and Probability: JEE Main 2025 Mathematics question

Let $x_1, x_2, \ldots, x_{10}$ be ten observations such that $\sum_{i=1}^{10}(x_i-2)=30$, $\sum_{i=1}^{10}(x_i-\beta)^2=98$, $\beta>2$, and their variance is $\frac{4}{5}$. If $\mu$ and $\sigma^2$ are respectively the mean and the variance of $2(x_1-1)+4\beta$, $2(x_2-1)+4\beta$, $\ldots$, $2(x_{10}-1)+4\beta$, then $\frac{\beta \mu}{\sigma^2}$ is equal to: