JEE Main 2025January, Unspecified (session-level dataset)MathematicsMediumComplex Numbers and Quadratic Equations264× since 2002If α+iβ\alpha + i\betaα+iβ and γ+iδ\gamma + i\deltaγ+iδ are the roots of x2−(3−2i)x−(2i−2)=0x^2 - (3 - 2i)x - (2i - 2) = 0x2−(3−2i)x−(2i−2)=0, i=−1i = \sqrt{-1}i=−1, then αγ+βδ\alpha\gamma + \beta\deltaαγ+βδ is equal to:AOption A. -2BOption B. 6COption C. -6DOption D. 2CheckSkip · show solution
