JEE Main 2025January, Unspecified (session-level dataset)MathematicsMediumIntegral Calculus369× since 2002The area of the region bounded by the curves x(1+y2)=1x(1 + y^2) = 1x(1+y2)=1 and y2=2xy^2 = 2xy2=2x is:AOption A. 2(π2−13)2\left(\frac{\pi}{2} - \frac{1}{3}\right)2(2π−31)BOption B. π2−13\frac{\pi}{2} - \frac{1}{3}2π−31COption C. π4−13\frac{\pi}{4} - \frac{1}{3}4π−31DOption D. 12(π2−13)\frac{1}{2}\left(\frac{\pi}{2} - \frac{1}{3}\right)21(2π−31)CheckSkip · show solution
