JEE Main 2025January, Unspecified (session-level dataset)MathematicsMediumLimit, Continuity and Differentiability420× since 2002limx→0cscx(2cos2x+3cosx−cos2x+sinx+4)\lim_{x \rightarrow 0} \csc x \left(\sqrt{2 \cos^2 x + 3 \cos x} - \sqrt{\cos^2 x + \sin x + 4}\right)limx→0cscx(2cos2x+3cosx−cos2x+sinx+4) is:AOption A. 0BOption B. 115\frac{1}{\sqrt{15}}151COption C. 125\frac{1}{2\sqrt{5}}251DOption D. −125-\frac{1}{2\sqrt{5}}−251CheckSkip · show solution