JEE Main 2025January, Unspecified (session-level dataset)MathematicsMediumTrigonometry118× since 2002The sum of all values of θ∈[0,2π]\theta \in [0, 2\pi]θ∈[0,2π] satisfying 2sin2θ=cos2θ2\sin^2 \theta = \cos 2\theta2sin2θ=cos2θ and 2cos2θ=3sinθ2\cos^2 \theta = 3\sin \theta2cos2θ=3sinθ is:AOption A. 4π4\pi4πBOption B. 5π6\frac{5\pi}{6}65πCOption C. π\piπDOption D. 52\frac{5}{2}25CheckSkip · show solution
