JEE Main 2025April, Unspecified (session-level dataset)MathematicsMediumTrigonometry118× since 2002The value of cot−1(1+tan2(2)−1tan(2))−cot−1(1+tan2(12)+1tan(12))\cot^{-1} \left( \frac{\sqrt{1 + \tan^2(2)} - 1}{\tan(2)} \right) - \cot^{-1} \left( \frac{\sqrt{1 + \tan^2\left(\frac{1}{2}\right)} + 1}{\tan\left(\frac{1}{2}\right)} \right)cot−1(tan(2)1+tan2(2)−1)−cot−1(tan(21)1+tan2(21)+1) is equal to:AOption A. π−54\pi - \frac{5}{4}π−45BOption B. π−32\pi - \frac{3}{2}π−23COption C. π+32\pi + \frac{3}{2}π+23DOption D. π+52\pi + \frac{5}{2}π+25CheckSkip · show solution
