JEE Main 2025April, Unspecified (session-level dataset)MathematicsMediumComplex Numbers and Quadratic Equations264× since 2002Let A={θ∈[0,2π]:1+10 Re(2cosθ+isinθcosθ−3isinθ)=0}.A = \left\{ \theta \in [0, 2\pi] : 1 + 10\,\text{Re} \left( \frac{2\cos\theta + i\sin\theta}{\cos\theta - 3i\sin\theta} \right) = 0 \right\}.A={θ∈[0,2π]:1+10Re(cosθ−3isinθ2cosθ+isinθ)=0}. Then ∑θ∈Aθ2\sum_{\theta \in A} \theta^2∑θ∈Aθ2 is equal to:AOption A. 214π2\frac{21}{4} \pi^2421π2BOption B. 8π28\pi^28π2COption C. 274π2\frac{27}{4} \pi^2427π2DOption D. 6π26\pi^26π2CheckSkip · show solution