Three Dimensional Geometry: JEE Main 2025 Mathematics question

Let the values of $\lambda$ for which the shortest distance between the lines $\frac{x-1}{2} = \frac{y-2}{3} = \frac{z-3}{4}$ and $\frac{x - \lambda}{3} = \frac{y - 4}{4} = \frac{z - 5}{5}$ is $\frac{1}{\sqrt{6}}$ be $\lambda_1$ and $\lambda_2$. Then the radius of the circle passing through the points (0, 0), $(\lambda_1, \lambda_2)$ and $(\lambda_2, \lambda_1)$ is