JEE Main 2025April, Unspecified (session-level dataset)MathematicsMediumTrigonometry118× since 2002If for θ∈[−π3,0]\theta \in \left[ -\frac{\pi}{3}, 0 \right]θ∈[−3π,0], the points (x,y)=(3tan(θ+π3),2tan(θ+π6))(x, y) = \left( 3 \tan\left(\theta + \frac{\pi}{3}\right), 2 \tan\left(\theta + \frac{\pi}{6}\right) \right)(x,y)=(3tan(θ+3π),2tan(θ+6π)) lie on xy+αx+βy+γ=0xy + \alpha x + \beta y + \gamma = 0xy+αx+βy+γ=0, then α2+β2+γ2\alpha^2 + \beta^2 + \gamma^2α2+β2+γ2 is equal to:AOption A. 80BOption B. 72COption C. 96DOption D. 75CheckSkip · show solution