JEE Main 2025April, Unspecified (session-level dataset)MathematicsMediumCoordinate Geometry478× since 2002The radius of the smallest circle which touches the parabolas y=x2+2y = x^2 + 2y=x2+2 and x=y2+2x = y^2 + 2x=y2+2 is:AOption A. 722\tfrac{7\sqrt{2}}{2}272BOption B. 7216\tfrac{7\sqrt{2}}{16}1672COption C. 724\tfrac{7\sqrt{2}}{4}472DOption D. 728\tfrac{7\sqrt{2}}{8}872CheckSkip · show solution
