JEE Main 202523 Jan, Morning shiftChemistryEasySome Basic Concepts in Chemistry88× since 20022.8×10−32.8\times10^{-3}2.8×10−3 mol of CO2\mathrm{CO_2}CO2 is left after removing 102110^{21}1021 molecules from its 'x' mg sample. The mass of CO2\mathrm{CO_2}CO2 taken initially is Given: NA=6.02×1023 mol−1N_A=6.02\times10^{23}\ \mathrm{mol^{-1}}NA=6.02×1023 mol−1AOption A. 196.2 mgBOption B. 98.3 mgCOption C. 48.2 mgDOption D. 150.4 mgCheckSkip · show solution
