FeO₄²⁻ + 2.2V F e³⁺ + 0.70V F e²⁺ - 0.45V F e⁰ E_ FeO₄²⁻/F e²⁺ ^θ is x × 10⁻³ V. The value of x is _ _ _ _ _

Redox Reactions and Electrochemistry: JEE Main 2023 Chemistry question

JEE Main 2023 · 10 Apr, Morning shift · Q13

JEE Main 202310 Apr, Morning shiftChemistryMediumRedox Reactions and Electrochemistry138× since 2002

\mathrm{FeO_4^{2 - }\buildrel { + 2.2V} \over \longrightarrow F{e^{3 + }}\buildrel { + 0.70V} \over \longrightarrow F{e^{2 + }}\buildrel { - 0.45V} \over \longrightarrow F{e^0}}

E_{FeO_4^{2 - }/F{e^{2 + }}}^\theta

x \times {10^{ - 3}}

V. The value of

x

is _________

Your answerType your answer. Integers and decimals are accepted.

JEE Main 2023 · 10 Apr, Morning shift · Q13

JEE Main 202310 Apr, Morning shiftChemistryMediumRedox Reactions and Electrochemistry138× since 2002

\mathrm{FeO_4^{2 - }\buildrel { + 2.2V} \over \longrightarrow F{e^{3 + }}\buildrel { + 0.70V} \over \longrightarrow F{e^{2 + }}\buildrel { - 0.45V} \over \longrightarrow F{e^0}}

E_{FeO_4^{2 - }/F{e^{2 + }}}^\theta

x \times {10^{ - 3}}

V. The value of

x

is _________

Your answerType your answer. Integers and decimals are accepted.