A₂+B₂ → 2 AB. Δ H f ⁰=-200 ~kJ ~mol⁻¹ AB, A₂ and B₂ are diatomic molecules. If the bond enthalpies of A₂, ~B₂ and AB are in the ratio 1: 0.5: 1, then the bond enthalpy of A₂ is _ _ _ _ _ _ kJ ~mol⁻¹ (Nearest integer)

Chemical Thermodynamics: JEE Main 2023 Chemistry question

JEE Main 2023 · 13 Apr, Morning shift · Q21

JEE Main 202313 Apr, Morning shiftChemistryHardChemical Thermodynamics84× since 2002

\mathrm{A}_{2}+\mathrm{B}_{2} \rightarrow 2 \mathrm{AB} . \Delta H_{f}^{0}=-200 \mathrm{~kJ} \mathrm{~mol}^{-1}

\mathrm{AB}, \mathrm{A}_{2}

and

\mathrm{B}_{2}

are diatomic molecules. If the bond enthalpies of

\mathrm{A}_{2}, \mathrm{~B}_{2}

and

\mathrm{AB}

are in the ratio

1: 0.5: 1

, then the bond enthalpy of

\mathrm{A}_{2}

is ____________

\mathrm{kJ} ~\mathrm{mol}^{-1}

(Nearest integer)

Your answerType your answer. Integers and decimals are accepted.

JEE Main 2023 Chemical Thermodynamics Question with Answer (13 Apr Morning shift, Q21) | JEE Arc