PhysicsMedium120×since 2002Q6741Magnetic field in a plane electromagnetic wave is given by B→\overrightarrow BB = B₀ sin (k x + ω\omegaωt) j^ T\widehat j\,TjT Expression for corresponding electric field will be : Where c is speed of light.AE→\overrightarrow EE = B₀ c sin (k x + ω\omegaωt) k^\widehat kk V/mBE→\overrightarrow EE = B0c{{{B_0}} \over c}cB0 sin (k x + ω\omegaωt) k^\widehat kk V/mCE→\overrightarrow EE = −-− B₀ c sin (kx +ω\omegaωt) k^\widehat kk V/mDE→\overrightarrow EE = B₀ c sin (kx −-−ω\omegaωt) k^\widehat kk V/mCheck answerSkip