PhysicsEasy120×since 2002Q6795Light wave travelling in air along x-direction is given by Ey=540sinπ×104(x−ct) Vm−1{E_y} = 540\sin \pi \times {10^4}(x - ct)\,V{m^{ - 1}}Ey=540sinπ×104(x−ct)Vm−1. Then, the peak value of magnetic field of wave will be (Given c = 3 ×\times× 10⁸ ms^−-−1)A18 ×\times× 10^−-−7 TB54 ×\times× 10^−-−7 TC54 ×\times× 10^−-−8 TD18 ×\times× 10^−-−8 TCheck answerSkip