MathematicsEasy63×since 2002Q3710Let y(x)=(1+x)(1+x2)(1+x4)(1+x8)(1+x16)y(x) = (1 + x)(1 + {x^2})(1 + {x^4})(1 + {x^8})(1 + {x^{16}})y(x)=(1+x)(1+x2)(1+x4)(1+x8)(1+x16). Then y′−y′′y' - y''y′−y′′ at x=−1x = - 1x=−1 is equal toA496B976C464D944Check answerSkip