Let the foot of perpendicular from the point (λ,2,3) on the line (x-4)/1=(y-9)/2=(z-5)/1 be the point (1,μ,2). Then the distance between the lines (x-1)/2=(y-2)/3=(z+4)/6 and (x-λ)/2=(y-μ)/3=(z+5)/6 is equal to:

Three Dimensional Geometry: JEE Main 2026 Mathematics question

JEE Main 2026 · 8 Apr, Evening shift · Q15

JEE Main 20268 Apr, Evening shiftMathematicsMediumThree Dimensional Geometry249× since 2002

Let the foot of perpendicular from the point

(\lambda,2,3)

on the line

\frac{x-4}{1}=\frac{y-9}{2}=\frac{z-5}{1}

be the point

(1,\mu,2)

. Then the distance between the lines

\frac{x-1}{2}=\frac{y-2}{3}=\frac{z+4}{6}

and

\frac{x-\lambda}{2}=\frac{y-\mu}{3}=\frac{z+5}{6}

is equal to :