Let the foci of a hyperbola coincide with the foci of the ellipse (x²)/36+(y²)/16=1. If the eccentricity of the hyperbola is 5, then the length of its latus rectum is:

Coordinate Geometry: JEE Main 2026 Mathematics question

JEE Main 2026 · 21 Jan, Morning shift · Q15

JEE Main 202621 Jan, Morning shiftMathematicsEasyCoordinate Geometry478× since 2002

Let the foci of a hyperbola coincide with the foci of the ellipse

\frac{x^2}{36}+\frac{y^2}{16}=1

. If the eccentricity of the hyperbola is 5, then the length of its latus rectum is :

JEE Main 2026 · 21 Jan, Morning shift · Q15

JEE Main 202621 Jan, Morning shiftMathematicsEasyCoordinate Geometry478× since 2002

Let the foci of a hyperbola coincide with the foci of the ellipse

\frac{x^2}{36}+\frac{y^2}{16}=1

. If the eccentricity of the hyperbola is 5, then the length of its latus rectum is :