Let the circle x² + y² = 4 intersect x-axis at the points A(a, 0), a > 0 and B(b, 0). Let P(2 cos α, 2 sin α), 0 < α < (π)/2 and Q(2 cos β, 2 sin β) be two points such that (α - β) = (π)/2. Then the point of intersection of AQ and BP lies on:

Coordinate Geometry: JEE Main 2026 Mathematics question

JEE Main 2026 · 28 Jan, Evening shift · Q15

JEE Main 202628 Jan, Evening shiftMathematicsMediumCoordinate Geometry478× since 2002

Let the circle

x^2 + y^2 = 4

intersect x-axis at the points

A(a, 0)

a > 0

and

B(b, 0)

. Let

P(2\cos\alpha, 2\sin\alpha)

0 < \alpha < \frac{\pi}{2}

and

Q(2\cos\beta, 2\sin\beta)

be two points such that

(\alpha - \beta) = \frac{\pi}{2}

. Then the point of intersection of AQ and BP lies on :