MathematicsMedium127×since 2002Q3140Let the centre of a circle C be (α,β)(\alpha, \beta)(α,β) and its radius r<8r < 8r<8. Let 3x+4y=243 x+4 y=243x+4y=24 and 3x−4y=323 x-4 y=323x−4y=32 be two tangents and 4x+3y=14 x+3 y=14x+3y=1 be a normal to C. Then (α−β+r)(\alpha-\beta+r)(α−β+r) is equal to :A7B9C5D6Check answerSkip