Let the area enclosed by the x-axis, and the tangent and normal drawn to the curve 4x³ - 3x y² + 6x² - 5xy - 8y² + 9x + 14 = 0 at the point (- 2, 3) be A. Then 8A is equal to _ _ _ _ _ _ _.

Integral Calculus: JEE Main 2022 Mathematics question

JEE Main 2022 · 25 Jul, Evening shift · Q27

JEE Main 202225 Jul, Evening shiftMathematicsMediumIntegral Calculus369× since 2002

Let the area enclosed by the x-axis, and the tangent and normal drawn to the curve

4{x^3} - 3x{y^2} + 6{x^2} - 5xy - 8{y^2} + 9x + 14 = 0

at the point (

-

2, 3) be A. Then 8A is equal to ______________.

Your answerType your answer. Integers and decimals are accepted.

JEE Main 2022 Integral Calculus Question with Answer (25 Jul Evening shift, Q27) | JEE Arc

JEE Main 2022 · 25 Jul, Evening shift · Q27

JEE Main 202225 Jul, Evening shiftMathematicsMediumIntegral Calculus369× since 2002

Let the area enclosed by the x-axis, and the tangent and normal drawn to the curve

4{x^3} - 3x{y^2} + 6{x^2} - 5xy - 8{y^2} + 9x + 14 = 0

at the point (

-

2, 3) be A. Then 8A is equal to ______________.

Your answerType your answer. Integers and decimals are accepted.