JEE Main 202131 Aug, Morning shiftMathematicsMediumIntegral Calculus369× since 2002Let [t] denote the greatest integer ≤\le≤ t. Then the value of 8.∫−121([2x]+∣x∣)dx8.\int\limits_{ - {1 \over 2}}^1 {([2x] + |x|)dx}8.−21∫1([2x]+∣x∣)dx is ___________.Your answerType your answer. Integers and decimals are accepted.CheckSkip · show solution