JEE Main 20266 Apr, Morning shiftMathematicsEasyTrigonometry118× since 2002Let S={θ∈(−2π,2π):cosθ+1=3sinθ}S=\{\theta\in(-2\pi,2\pi):\cos\theta+1=\sqrt3\sin\theta\}S={θ∈(−2π,2π):cosθ+1=3sinθ}. Then ∑θ∈Sθ\sum_{\theta\in S}\theta∑θ∈Sθ is equal to:AOption A. −2π3-\frac{2\pi}{3}−32πBOption B. −4π3-\frac{4\pi}{3}−34πCOption C. 2π3\frac{2\pi}{3}32πDOption D. 4π3\frac{4\pi}{3}34πCheckSkip · show solution
