Let S = C: |(z - 6i)/(z - 2i)| = 1 and |(z - 8 + 2i)/(z + 2i)| = 3/5. Then Σ z S |z|² is equal to

Complex Numbers and Quadratic Equations: JEE Main 2026 Mathematics question

JEE Main 2026 · 24 Jan, Morning shift · Q19

JEE Main 202624 Jan, Morning shiftMathematicsEasyComplex Numbers and Quadratic Equations264× since 2002

Let

S = \left\{z \in \mathbb{C} : \left|\frac{z - 6i}{z - 2i}\right| = 1 \text{ and } \left|\frac{z - 8 + 2i}{z + 2i}\right| = \frac{3}{5}\right\}

. Then

\sum_{z \in S} |z|^2

is equal to

JEE Main 2026 · 24 Jan, Morning shift · Q19

JEE Main 202624 Jan, Morning shiftMathematicsEasyComplex Numbers and Quadratic Equations264× since 2002

Let

S = \left\{z \in \mathbb{C} : \left|\frac{z - 6i}{z - 2i}\right| = 1 \text{ and } \left|\frac{z - 8 + 2i}{z + 2i}\right| = \frac{3}{5}\right\}

. Then

\sum_{z \in S} |z|^2

is equal to