JEE Main 20265 Apr, Morning shiftMathematicsEasyComplex Numbers and Quadratic Equations264× since 2002Let a,b∈Ca, b \in \mathbb{C}a,b∈C. Let α,β\alpha, \betaα,β be the roots of the equation x2+ax+b=0x^2 + ax + b = 0x2+ax+b=0. If β−α=11\beta - \alpha = \sqrt{11}β−α=11 and β2−α2=3i11\beta^2 - \alpha^2 = 3i\sqrt{11}β2−α2=3i11, then (β3−α3)2(\beta^3 - \alpha^3)^2(β3−α3)2 is equal to:AOption A. 160BOption B. 176COption C. 194DOption D. 187CheckSkip · show solution
