JEE Main 202624 Jan, Morning shiftMathematicsMediumVector Algebra184× since 2002Let a⃗=2i^+j^−2k^\vec{a} = 2\hat{i} + \hat{j} - 2\hat{k}a=2i^+j^−2k^, b⃗=i^+j^\vec{b} = \hat{i} + \hat{j}b=i^+j^ and c⃗=a⃗×b⃗\vec{c} = \vec{a} \times \vec{b}c=a×b. Let d⃗\vec{d}d be a vector such that ∣d⃗−a⃗∣=11|\vec{d} - \vec{a}| = \sqrt{11}∣d−a∣=11, ∣c⃗×d⃗∣=3|\vec{c} \times \vec{d}| = 3∣c×d∣=3 and the angle between c⃗\vec{c}c and d⃗\vec{d}d is π4\frac{\pi}{4}4π. Then a⃗⋅d⃗\vec{a} \cdot \vec{d}a⋅d is equal toAOption A. 111111BOption B. 000COption C. 333DOption D. 111CheckSkip · show solution