JEE Main 20264 Apr, Morning shiftMathematicsEasyIntegral Calculus369× since 2002Let ∫−22(∣sinx∣+[xsinx])dx=2(3−cos2)+β\int_{-2}^{2}\left(|\sin x|+[x\sin x]\right)dx=2(3-\cos2)+\beta∫−22(∣sinx∣+[xsinx])dx=2(3−cos2)+β, where [⋅][\cdot][⋅] is the greatest integer function. Then βsin(β2)\beta\sin\left(\frac{\beta}{2}\right)βsin(2β) equals:AOption A. 1BOption B. 2COption C. 4DOption D. 8CheckSkip · show solution
