Let f(α) denote the area of the region in the first quadrant bounded by x=0, x=1, y²=x and y=|α x-5|-|1-α x|+α x². Then (f(0)+f(1)) is equal to

Integral Calculus: JEE Main 2026 Mathematics question

JEE Main 2026 · 24 Jan, Evening shift · Q18

JEE Main 202624 Jan, Evening shiftMathematicsEasyIntegral Calculus369× since 2002

Let

f(\alpha)

denote the area of the region in the first quadrant bounded by

x=0

x=1

y^2=x

and

y=|\alpha x-5|-|1-\alpha x|+\alpha x^2

. Then

(f(0)+f(1))

is equal to

JEE Main 2026 · 24 Jan, Evening shift · Q18

JEE Main 202624 Jan, Evening shiftMathematicsEasyIntegral Calculus369× since 2002

Let

f(\alpha)

denote the area of the region in the first quadrant bounded by

x=0

x=1

y^2=x

and

y=|\alpha x-5|-|1-\alpha x|+\alpha x^2

. Then

(f(0)+f(1))

is equal to