MathematicsMedium127×since 2002Q3074Let C be a circle passing through the points A(2, −-−1) and B(3, 4). The line segment AB s not a diameter of C. If r is the radius of C and its centre lies on the circle (x−5)2+(y−1)2=132{(x - 5)^2} + {(y - 1)^2} = {{13} \over 2}(x−5)2+(y−1)2=213, then r² is equal to :A32B652{{65} \over 2}265C612{{61} \over 2}261D30Check answerSkip