JEE Main 202621 Jan, Evening shiftMathematicsEasyDifferential Equations163× since 2002Let y=y(x)y=y(x)y=y(x) be the solution of the differential equation secxdydx−2y=2+3sinx\sec x\frac{dy}{dx}-2y=2+3\sin xsecxdxdy−2y=2+3sinx, x∈(−π2,π2)x\in\left(-\frac{\pi}{2}, \frac{\pi}{2}\right)x∈(−2π,2π), y(0)=−74y(0)=-\frac{7}{4}y(0)=−47. Then y(π6)y\left(\frac{\pi}{6}\right)y(6π) is equal to :AOption A. −52-\frac{5}{2}−25BOption B. −54-\frac{5}{4}−45COption C. −33−7-3\sqrt{3}-7−33−7DOption D. −32−7-3\sqrt{2}-7−32−7CheckSkip · show solution
