MathematicsEasy129×since 2002Q5071Let S\mathrm{S}S be the set of positive integral values of aaa for which ax2+2(a+1)x+9a+4x2−8x+32<0,∀x∈R\frac{a x^2+2(a+1) x+9 a+4}{x^2-8 x+32} < 0, \forall x \in \mathbb{R}x2−8x+32ax2+2(a+1)x+9a+4<0,∀x∈R. Then, the number of elements in S\mathrm{S}S is :A0B∞\infty∞C3D1Check answerSkip