MathematicsEasy129×since 2002Q5114Let two numbers have arithmetic mean 9 and geometric mean 4. Then these numbers are the roots of the quadratic equationAx2−18x−16=0{x^2} - 18x - 16 = 0x2−18x−16=0Bx2−18x+16=0{x^2} - 18x + 16 = 0x2−18x+16=0Cx2+18x−16=0{x^2} + 18x - 16 = 0x2+18x−16=0Dx2+18x+16=0{x^2} + 18x + 16 = 0x2+18x+16=0Check answerSkip