MathematicsHard129×since 2002Q5163Let α,β\alpha, \betaα,β be the roots of the quadratic equation x2+6x+3=0x^{2}+\sqrt{6} x+3=0x2+6x+3=0. Then α23+β23+α14+β14α15+β15+α10+β10\frac{\alpha^{23}+\beta^{23}+\alpha^{14}+\beta^{14}}{\alpha^{15}+\beta^{15}+\alpha^{10}+\beta^{10}}α15+β15+α10+β10α23+β23+α14+β14 is equal to :A72B9C729D81Check answerSkip