MathematicsHard129×since 2002Q5162Let α,β\alpha, \betaα,β be the roots of the equation x2−2x+2=0x^{2}-\sqrt{2} x+2=0x2−2x+2=0. Then α14+β14\alpha^{14}+\beta^{14}α14+β14 is equal toA−64-64−64B−642-64 \sqrt{2}−642C−1282-128 \sqrt{2}−1282D−128-128−128Check answerSkip