JEE Main 20265 Apr, Evening shiftMathematicsEasyComplex Numbers and Quadratic Equations264× since 2002Let z1,z2∈Cz_1, z_2 \in \mathbb{C}z1,z2∈C be the distinct solutions of the equation z2+4z−(1+12i)=0z^2+4z-(1+12i)=0z2+4z−(1+12i)=0. Then ∣z1∣2+∣z2∣2|z_1|^2+|z_2|^2∣z1∣2+∣z2∣2 is equal to :AOption A. 18BOption B. 22COption C. 29DOption D. 34CheckSkip · show solution
