MathematicsEasy129×since 2002Q5172Let α,β\alpha, \betaα,β be the distinct roots of the equation x2−(t2−5t+6)x+1=0,t∈Rx^2-\left(t^2-5 t+6\right) x+1=0, t \in \mathbb{R}x2−(t2−5t+6)x+1=0,t∈R and an=αn+βna_n=\alpha^n+\beta^nan=αn+βn. Then the minimum value of a2023+a2025a2024\frac{a_{2023}+a_{2025}}{a_{2024}}a2024a2023+a2025 isA−1/2-1 / 2−1/2B−1/4-1 / 4−1/4C1/41 / 41/4D1/21 / 21/2Check answerSkip