JEE Main 20265 Apr, Evening shiftMathematicsMediumMatrices and Determinants245× since 2002Let MMM be a 3×33\times33×3 matrix such that M(100)=(123)M\begin{pmatrix}1\\0\\0\end{pmatrix}=\begin{pmatrix}1\\2\\3\end{pmatrix}M100=123, M(010)=(012)M\begin{pmatrix}0\\1\\0\end{pmatrix}=\begin{pmatrix}0\\1\\2\end{pmatrix}M010=012 and M(001)=(−111)M\begin{pmatrix}0\\0\\1\end{pmatrix}=\begin{pmatrix}-1\\1\\1\end{pmatrix}M001=−111. If M(xyz)=(1711)M\begin{pmatrix}x\\y\\z\end{pmatrix}=\begin{pmatrix}1\\7\\11\end{pmatrix}Mxyz=1711, then x+y+zx+y+zx+y+z equals :AOption A. 4BOption B. 5COption C. 7DOption D. 11CheckSkip · show solution
