JEE Main 202623 Jan, Morning shiftMathematicsMediumTrigonometry118× since 2002Let α\alphaα and β\betaβ respectively be the maximum and the minimum values of the function f(θ)=4(sin4(7π2−θ)+sin4(11π+θ))−2(sin6(3π2−θ)+sin6(9π−θ))f(\theta)=4\left(\sin^4\left(\frac{7\pi}{2}-\theta\right)+\sin^4(11\pi+\theta)\right)-2\left(\sin^6\left(\frac{3\pi}{2}-\theta\right)+\sin^6(9\pi-\theta)\right)f(θ)=4(sin4(27π−θ)+sin4(11π+θ))−2(sin6(23π−θ)+sin6(9π−θ)), θ∈R\theta\in\mathbb{R}θ∈R. Then α+2β\alpha+2\betaα+2β is equal to :AOption A. 4BOption B. 3COption C. 6DOption D. 5CheckSkip · show solution
