JEE Main 20266 Apr, Morning shiftMathematicsEasyTrigonometry118× since 2002Let 0<α<10<\alpha<10<α<1, β=13α\beta=\frac{1}{3\alpha}β=3α1 and tan−1(1−α)+tan−1(1−β)=π4\tan^{-1}(1-\alpha)+\tan^{-1}(1-\beta)=\frac{\pi}{4}tan−1(1−α)+tan−1(1−β)=4π. Then 6(α+β)6(\alpha+\beta)6(α+β) is equal to:AOption A. 6BOption B. 7COption C. 8DOption D. 9CheckSkip · show solution
